Creating an Array with nested for loops.
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If I have an array say A = 1:4, how would I create a new 1 x 7 array with the following elements and structure with a nested for loop? I'm very confused.
4 4 4 4 4 4 4
4 3 3 3 3 3 4
4 3 2 2 2 3 4
4 3 2 1 2 3 4
4 3 2 2 2 3 4
4 3 3 3 3 3 4
4 4 4 4 4 4 4
1 个评论
@Nikko Jeffreys: I edited your question and replaced the example that you just deleted. Please do not delete or edit questions so that they do not make sense. We are not your personal MATLAB help service: we are volunteers here to help everyone who reads this forum. When you edit your question and remove all useful information you make our answers useless for anyone else reading this forum, the exact people we volunteer to help.
采纳的回答
Andrei Bobrov
2016-9-19
编辑：Andrei Bobrov
2016-9-19
A = 1:4;
m = numel(A);
[ii,jj] = ndgrid(1:2*m-1);
out = A(max(abs(ii-m),abs(jj-m))+1);
or
m = numel(A);
s = zeros(2*m-1);
s(m,m) = 1;
out = A(bwdist(s,'chessboard')+1);
or with for..end loop
m = numel(A);
out = zeros(2*m-1);
for jj = 1:m
out(jj:m*2-jj,jj:m*2-jj) = A(m + 1 -jj);
end
更多回答（2 个）
Using a for loop:
A = 1:4;
N = numel(A);
B = NaN(2*N-1);
for k = 1:N
B([N+k-1,N-k+1],:) = A(k);
B(:,[N+k-1,N-k+1]) = A(k);
end
KSSV
2016-9-19
B = ones(7) ;
B(1,:) = 4 ; B(2,2:end-1) = 3 ;B(3,3:end-2)=2 ;
B(:,1) = 4 ; B(2:end-1,2) = 3 ;B(3:end-2,3)=2 ;
B(:,end) = 4 ;B(2:end-1,end-1) = 3 ;B(3:end-2,end-2)=2 ;
B(end,:) = 4 ;B(end-1,2:end-1)=3 ;B(end-2,3:end-2)=2 ;
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