how to remove last characther from cell array of string

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Mederic Mainson
Mederic Mainson 2016-9-22
评论： Walter Roberson 2016-9-22
Hi All, let's say i have this cell array of string:
test={'1234T'; '4567T'; '8901T'};
Is the a way to remove the last character T on every cell using this kind of command:
test=test{:}(1:end-1);
If not what is the best way to do it without loop? Cheers Medie
  2 个评论
Mederic Mainson
Mederic Mainson 2016-9-22
Hi, I think i found the best way...
test= cellfun(@(x) x(1:end-1), test, 'UniformOutput', false);
Is it the best way?
Walter Roberson
Walter Roberson 2016-9-22
It is a good way. Depending how large the array is, it is possible that regexprep might be faster on large matrices; I would need to benchmark to verify that though.

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Walter Roberson
Walter Roberson 2016-9-22
I have not looked at all carefully, but if you are using R2016b then I gather the new string data type has functions that can be used for this kind of thing without using a loop.
Other than that there are multiple ways. The easiest is probably
test = cellfun(@(S) S(1:end-1), test, 'Uniform', 0);
which uses an implicit loop.
You could also use
test = regexprep(test, '.$', '', 'lineanchors');
which means "replace the character right before the end of string with nothingness"

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