How can I count frequency in array?

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I try to make a code which count the frequency of number in an array but the number output is incorrect. my coding:
clc; clear; element = zeros (1,50); ctr=1; i=1; freq=0;
num = input('Please state how many numbers you want to input: ');
while (ctr <= num) %input number in array
element (ctr) = input( 'Enter number: ');
ctr = ctr+1;
end
for ctr=1:1:num %to arrange number in descending
for i=1:1:num
if element (i) < element (i+1)
temp = element(i);
element (i) = element (i+1);
element (i+1) = temp;
end
end
end
disp('N Count');
for y=1:1:num %counting frequency of number
k = element(y);
if k ~= element (y+1)
for x = y:1:num
if k == element (x+1)
freq = freq+1;
end
end
fprintf('%d','%d',k, freq);
end
freq=0;
end
pause;
The output is as follow:
Please state how many numbers you want to input: 2 Enter number: 1 Enter number: 2 N Count 37100203710010

采纳的回答

George
George 2016-9-24
fprintf prints to a file. You want to use sprintf. Also, your formatSpec is wrong. You want to define it as one string. Something like:
str = sprintf('%d %d', k, freq);
disp(str)
Should work.
  3 个评论
fizz gerbera
fizz gerbera 2016-9-24
编辑:fizz gerbera 2016-9-24
thanks george. it can print the answer fine now. i tried to your suggestion.my coding is as follows, but i cant seem to make it work.
while k<=num
sum(nnz(A == k));
fprint('%d', k);
k=k+1;
end
George
George 2016-9-24
You should not be using fprintf.

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