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Vectors must be the same length, Table

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Amritpal Kaur
Amritpal Kaur 2016-9-25
编辑： Image Analyst 2016-9-25
Hello,
So I have some uneven data tables like this:
And whenever I try to plot something like this:
plot(BackPocket.Ax, Ear.Ax)
I get the following error:
Vectors must be the same length.
How can I get past this by truncating, removing etc. non-matching rows?
Thanks.

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Image Analyst
Image Analyst 2016-9-25
How can you plot Ear vs. BackPocket if they don't have the same number of elements? Do you want to plot each separately versus their index? If so
plot(BackPocket.Ax, 'b*-');
hold on;
plot(Ear.Ax, 'rd-');
  2 个评论
Amritpal Kaur
Amritpal Kaur 2016-9-25
No I just want to truncate the one table that has more data to match the one that has less. Any easy way to do this?
Image Analyst
Image Analyst 2016-9-25
编辑：Image Analyst 2016-9-25
Find the number of rows and plot the min
rows = min([length(BackPocket.Ax), length(Ears.Ax)]);
plot(BackPocket(1:rows).Ax, plot(Ear(1:rows).Ax, 'b*-');
Or maybe it's
plot(BackPocket{1:rows}.Ax, plot(Ear{1:rows}.Ax, 'b*-');
Or maybe it's
plot(BackPocket.Ax(1:rows), plot(Ear.Ax(1:rows), 'b*-');
-- not sure without trying it.

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