If all the 20 datenum vectors has the same length, the following (though not straight forward) could work.
- Concatenate all the vectors into one column vector.
- Sort it.
- Find indexes where the difference is smaller than 3 (some threshold).
- Find the corresponding indexes in the original vector.
A=[712549, 712658, 715188, 715935, 716613, 716948, 717319, 717764, 718091, 718484];
B =[714401, 716219, 717321, 717716, 718506, 718802, 722427, 722853, 723546, 723554];
C =[718802, 722427, 722853, 723546, 723554, 724633, 726821, 731624, 731958, 733730];
All = [A', B', C'];
% 1: Concatenate all the vectors into one column vector.
Alldata = All(:);
% 2: Sort it. (index refers to the original location in Alldata)
[sorted,index] = sort(Alldata);
% 3: Find indexes where the difference is smaller than 3 (some threshold).
idx_close = find(diff(sorted) < 3);
% 4: Find the corresponding indexes in the original vector.
a0 = Index(idx_close);
a1 = Index(idx_close+1);
[I0,J0] = ind2sub([10,3],a0); % 10 : length of the datenum vector
[I1,J1] = ind2sub([10,3],a1); % 3 : number of variables (A, B, C)
% Now we know that All(I0,J0) is close to All(I1,J1). Let's display it.
variable_name = ['A','B','C'];
for ii=1:length(I0)
str0 = [variable_name(J0(ii)), ' ', num2str(All(I0(ii),J0(ii)))];
str1 = [variable_name(J1(ii)), ' ', num2str(All(I1(ii),J1(ii)))];
disp(['match : ', str0, ' and ', str1]);
end
