Get several subsets from a set using two arrays.
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Hello.
For example.
I have the following set:
exSet = 21:40;
And 2 arrays, one with the indexes of the lower position and the second with the indexes of the higher position.
Lower position array:
lPos = [2 8];
Upper position array:
uPos = [11 16];
The resulting subsets are:
subSet1 = extSet(lPos(1) : uPos(1)) = 22:31;
subSet2 = extSet(lPos(2) : uPos(2)) = 28:36;
But, I want to do this in a single step because both my set exSet and the arrays have much more elements.
To avoid a for loop, I will appreciate suggestions.
Best Regards,
采纳的回答
Massimo Zanetti
2016-9-28
编辑：Massimo Zanetti
2016-9-28
Ok, I got it. You can work like this, by exploiting arrayfun, which iterates an operation on array elements.
vect = 101:120;
s(1).lim=[11,15];
s(2).lim=[4,9];
s(3).lim=[9,18];
ext = arrayfun( @(x) vect(x.lim(1):x.lim(2)) , s , 'UniformOutput' , false);
ext{1}
ext{2}
ext{3}
As you can see, in just one call, it is possible to extact from vect as many sub-vectors as we want. :)
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