Numerical integration with a variable integration limit

2016 9 28
2 个回答
更新时间：2016 9 29
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Is there a way to implement the following:
f2=@(z) integral (@(x) f1(x,z) ,0 ,z);
P2=@(z) integral(f2,z,Inf);
With f2 and P2 as two separate anonymous functions? It seems z in f2 must be a scalar (not a vector), so a for loop is required to make multiple evaluations at z I can deal with that, but Matlab will not evaluate P2, giving the error: Error using integral (line 85) A and B must be floating-point scalars.
It appears that
P2Alt=@(z) integral2(@(x,z) f1(x,z), 0, z, z, Inf);
accomplishes the desired end result (z must be a scalar), but I would prefer the function f2, separate.

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回答（2 个）

Ujjal Dey
Ujjal Dey 2016-9-29

0 个投票

At first, try with "int" command and form a final function of your desired variable. Ex: f2=@(x) int (f1(x,z),z);

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JohnM
JohnM 2016-9-29
Hi Ujjal. I should have mentioned in my post that I don't have the symbolic math toolbox, so invoking int is not an option for me.

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JohnM
JohnM 2016-9-29

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After giving this some thought, the following appears to be one way to solve the problem:
f2=@(z) integral(@(x) f1(x,z), 0, z);
f2Vect=@(z) arrayfun(@(z)f2(z),z); %vectorize f2
zval=0:0.1:3;
P2=zeros(1,length(zval)); %Preallocate
for i=1:length(zval)
P2(i)=integral(f2Vect,zval(i),Inf); %Evaluate the integral of f2
end

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JohnM
JohnM
2016-9-28

回答：

JohnM
JohnM
2016-9-29

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