Convert date to specific format julian date

2016 10 3
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更新时间：2016 10 4
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Need to convert calendar date to Julian date in a specific format (YYDDD). Ex: Day = (2016-05-04,2016-08-24,2016-12-31) J-Day = (16125,16237,16366)
Any help would be appreciated. Thanks.

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Gareth Thomas
Gareth Thomas 2016-10-3

2 个投票

Datetime works nicely. I believe it came out in R2014b.
see the Datetime function
a = datetime('2016-05-04');
a.Format='yyddd'

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Gareth Thomas
Gareth Thomas 2016-10-3
编辑：Gareth Thomas 2016-10-3
Sorry you also may need to use the command days , that calculates the number of days.
Charlie Wood
Charlie Wood 2016-10-3
编辑：Charlie Wood 2016-10-3
The result come out as:
a = 16004
Any way to get the actual day in the year number (125)? Thanks.
Peter Perkins
Peter Perkins 2016-10-3
If you are looking to get a string, Gareth was on the right track, just off by case:
>> a = datetime('2016-05-04')
a =
datetime
04-May-2016
>> char(a,'yyDDD')
ans =
'16125'
Of course, the whole point of datetime is to not have to convert between representations all the time, so perhaps
>> a.Format='yyDDD'
a =
16125
would serve as well. If you want a number, then your accepted answer is the way to go.
Charlie Wood
Charlie Wood 2016-10-4
编辑：Charlie Wood 2016-10-4
Peter/Gareth, this is perfect. Switching the ddd to DDD was the fix needed in the a.Format.
>> a = datetime('2016-05-04');
>> a.Format='yyDDD'
a =
16125
This works for any year as well which is great. This will be new accepted answer vice the numerical version I put up.
Thanks a gain for the help!

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更多回答（4 个）

Steven Lord
Steven Lord 2016-10-3

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Create a datetime array from the char vectors containing the yyyy-MM-dd form of the dates. Use the juliandate function to compute the Julian date from the datetime array.

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Charlie Wood
Charlie Wood 2016-10-3
编辑：Charlie Wood 2016-10-3
d = '2016-12-31';
dt = datetime(d)
dt = 31-Dec-2016
j = juliandate(dt)
j = 2.4578e+06
How do I get j into the yyddd format (to read 16366)?
Thanks.

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Michael C.
Michael C. 2016-10-3

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My understanding was that Julian usually referred to the number of days since Jan 1 4713 BC, but judging by your example, you are using March 11th, 1972.
Either way, you can get number of days by doing a subtraction on two "datenum"s
datenum([2016 08 24 0 0 0]) - datenum([1972 3 11 0 0 0])
which gives the 16237. Passing in a string for the date will also work.

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Charlie Wood
Charlie Wood 2016-10-3
This worked pretty effectively. Unfortunately if I have a date from 2015 or 2014 (which I do), it doesn't work as well. I guess I can put an if statement in there to switch the second datenum to the right value. Thanks so much Michael.

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Charlie Wood
Charlie Wood 2016-10-3

0 个投票

Here's what I got combining some answers:
d = '2016-05-04';
dt = datime(d);
jday = (year(dt)-2000)*1000 + day(dt,'dayofyear')
The answer comes out with 16125. It's not pretty and not useful for dates before the year 2010 (maybe with some minor formatting it would be ok for 2000-2009). It does however work for my 2014-2016 dates so far.
Thanks to everyone for the help and input!!!
Ankit Kanthe
Ankit Kanthe 2016-10-3

0 个投票

Here's what I got combining some answers:
d = '2016-05-04'; dt = datime(d); jday = (year(dt)-2000)*1000 + day(dt,'dayofyear') The answer comes out with 16125. It's not pretty and not useful for dates before the year 2010 (maybe with some minor formatting it would be ok for 2000-2009). It does however work for my 2014-2016 dates so far.

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