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concatonate time axis using a loop

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Jordan Gallacher
Jordan Gallacher 2016-10-4
关闭： MATLAB Answer Bot 2021-8-20
I have a time axis which keeps resetting due to drop outs in the logging e.g.
t = 0,1,2,3,4,5,0,1,2,3,4,5,6,7,8,9,10,0,1,2,3,4,5,6,7,8,9,10,0,1,2 and so on....
What is the most efficient piece of code to generate the new time vector so that the zeros continue on from the last time value before the dropout.
t = 0,1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,21,22,23,24,25,26,27,28,29,30
Thanks!
Jordan.
  1 个评论
Adam
Adam 2016-10-5
编辑：Adam 2016-10-5
I assume your real problem is a little more complex than the example you posted because to get that time vector you can just do
t = 0:numel(t) - 1;

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回答（1 个）

Marc Jakobi
Marc Jakobi 2016-10-5
This should do it:
t = [0,1,2,3,4,5,0,1,2,3,4,5,6,7,8,9,10,0,1,2,3,4,5,6,7,8,9,10,0,1,2];
idx = find(ismember(t, 0));
for i = 2:length(idx)-1
t(idx(i):idx(i+1) - 1) = t(idx(i):idx(i+1) - 1) + idx(i) - 1;
end
t(idx(end):end) = t(idx(end):end) + idx(end) - 1;
  2 个评论
Jordan Gallacher
Jordan Gallacher 2016-10-5
Hi Marc,
Thanks! What about if the zero was not exactly zero and say 4 microseconds i.e. just a value less than the last time value before the logging reset?
Thanks,
Jordan.
Marc Jakobi
Marc Jakobi 2016-10-5
编辑：Marc Jakobi 2016-10-5
Then I would I would replace
idx = find(ismember(t, 0));
with
idx = find([0, diff(t)] <= 0);

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