plotting circles
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How can I plot circles, same radius and different centers, all in one graph. I used the following command to draw +,o,diamond: plot (x,y,'ro',u,v,'gd',A,B,'b+'); where x,y,u,v,A,B are all row vectors. And I want to add circles to that plot where the o will be the center.
1 个评论
fatima ibrahim
2020-2-29
function draw_circle1(x,y,R,c)
t =0:0.05:6.28;
x1 = (x +R*cos(t))';
y1= (x +R*sin(t))';
采纳的回答
Paulo Silva
2011-3-12
Here's a function to draw circles:
function circle(x,y,r)
%x and y are the coordinates of the center of the circle
%r is the radius of the circle
%0.01 is the angle step, bigger values will draw the circle faster but
%you might notice imperfections (not very smooth)
ang=0:0.01:2*pi;
xp=r*cos(ang);
yp=r*sin(ang);
plot(x+xp,y+yp);
end
If you want to add circles you must insert the command
hold on
before the circles being added.
8 个评论
Firas
2014-12-29
That's awesome
Eddie
2017-3-15
Thanks a lot, this is great. If I had some time, I would probably tweak your code and try to plot open intervals on the real line, that's what I really need, but circles are fine too.
Bud Kelly
2018-4-2
There are coding solutions and there are coding solutions. The ones that accomplish the task as this one does are...elegant... beautiful... art. Thank you, you may consider it stolen! ;-)
passioncoding
2018-8-20
I have been trying to create function for circle with function that mentioned above ,but I am getting this "Not enough input arguments" for "xp=r*cos(ang)". kindly help me in this regard
Image Analyst
2018-8-20
编辑：Image Analyst
2018-8-20
What is ang for you? Did you comment out or delete the line
ang=0:0.01:2*pi;
??? You did one or the other because if you didn't, ang would exist and you would not get that error.
Do you know how to debug by setting a breakpoint on that line and looking at its value? If not, see this link
Özgür Saglam
2020-5-3
what does 0.01 in ang mean? i dont understand this part
Rik
2020-5-3
It's the step size. You can use the colon in two ways when you create an array:
start:stop
start:step:stop
Özgür Saglam
2020-5-3
Thank you very much!
更多回答（3 个）
Michelle Hirsch
2016-1-29
It's counter-intuitive, but this is actually really easy with the rectangle function. From the rectangle documentation :
pos = [2 4 2 2];
rectangle('Position',pos,'Curvature',[1 1])
axis equal
5 个评论
numCircles = 15;
x = 5 + randi(95, numCircles, 1);
y = 5 + randi(95, numCircles, 1);
radius = 2 * ones(numCircles, 1);
viscircles([x, y], radius);
grid on;
axis equal
Ronald Mintz
2016-4-14
Thanks very much Michelle. Your idea made beautiful concentric circles. viscircles didn't work on my computer because I have version R2011a.
rectangle() is one of several methods listed in the FAQ: http://matlab.wikia.com/wiki/FAQ#How_do_I_create_a_circle.3F> You'll have lots of other nice improvements that they've made over the last 5 years if you upgrade.
numCircles = 15;
x = 5 + randi(95, numCircles, 1);
y = 5 + randi(95, numCircles, 1);
radius = 2 * ones(numCircles, 1);
viscircles([x, y], radius);
grid on;
axis equal
Royi Avital
2023-12-10
It makes easier when adding it to the legend.
Michelle Hirsch
2023-12-11
@Royi Avital I think it's more than just adding DisplayName - annotations like rectangle (intentionally) don't show up in legend since they are meant to be annotations, not data. Are you interested in being able to include annotations in legend? If so, please share more about your use case so I make sure we understand what you are thinking.
There is now a function called viscircles(): http://www.mathworks.com/help/images/ref/viscircles.html?s_tid=srchtitle
numCircles = 15;
x = 5 + randi(95, numCircles, 1);
y = 5 + randi(95, numCircles, 1);
radius = 2 * ones(numCircles, 1);
viscircles([x, y], radius);
grid on;
axis equal
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