Morton scanning ?

Question

vishnu 2012-2-29

0
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此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/30615-morton-scanning

hi ,

i have to implement the morton scanning .. the idea is 
 image is to be separated as block and it is to be applied with morton Z scanning .  1& 2& 3 pixel is to be added and 4 th pixel to be divided by above sum .. this repeats further.. i have completed separating as blocks .. but i  do not have any idea of that processing . any one help or give suggestions please

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vishnu 2012-3-1

i found this function as for morton scanning ..but i don no how to use it for morton scanning .. criteria is i have an image ..divided by 4*4 blocks .. 1 ,2,3 pixels are added and fourth pixel is divided by above sum .. i don no how to use this function ..

function A = mapping(n)

% To create a Morton Scan order matrix

if n == 2

A = [1 2; 3 4];

else

B = mapping(n/2);

A = [B B+(n/2)^2; B+(n/2)^2*2 B+(n/2)^2*3];

end

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Answer 1

vishnu 2012-3-1

0
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此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/30615-morton-scanning#answer_39228

在 MATLAB Online 中打开

i found out this as for 4*4 matrix from matlab central

 clc;
 clear all;
 close all ;
 n=2;
 ind=morton(n);
 a=reshape(1:4^n,2^n,2^n);
 disp(a)

here is the matlab function

function ind=morton(n); % MORTON(N) return the morton permutation order for array of size 2^N % e.g. % n=2; % matrix size is 2^n % ind=morton(n); % d=fix(rand(2^n,2^n)*10); % disp(d) % disp(d(ind))

 linind4=(1:4^n)-1; %start index count for array at zero
 ind4str=dec2base(linind4,4); %convert indices to base-4
 b1=dec2bin(str2num(ind4str(:,1))); %split each base-4 into two base-2numbers
 b2=dec2bin(str2num(ind4str(:,2)));
 rb=[b1(:,1) b2(:,1)]; %the rows are given by the first bits of b1 and
 b2
 cb=[b1(:,2) b2(:,2)]; %the columns are given by the second bits of b1 and b2
 r=bin2dec(rb)+1; %convert the row from bit to decimal
 c=bin2dec(cb)+1; %convert column
 ind=[2^n*(c-1)+r]'; %make a linear row index into array for easyaddressing
 %morton.m ends
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