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Delete rows from Cell Array

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Tyler Smith
Tyler Smith 2016-10-7
回答： Hedayat 2019-11-28
I have a cell array as seen in the image. I want to delete the rows of the cell array where the first column is less than 3. Thanks.

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采纳的回答

Walter Roberson
Walter Roberson 2016-10-7
mask = cell2mat(YourCell(:,1)) < 3;
YourCell(mask, :) = [];

更多回答（2 个）

Hedayat
Hedayat 2019-11-28
If you want to delete more than one rows of cell you can ...
a= cell(5,5)
a =
5×5 cell array
{0×0 double} {0×0 double} {0×0 double} {0×0 double} {0×0 double}
{0×0 double} {0×0 double} {0×0 double} {0×0 double} {0×0 double}
{0×0 double} {0×0 double} {0×0 double} {0×0 double} {0×0 double}
{0×0 double} {0×0 double} {0×0 double} {0×0 double} {0×0 double}
{0×0 double} {0×0 double} {0×0 double} {0×0 double} {0×0 double}
a([2,3],:)=[]
a =
3×5 cell array
{0×0 double} {0×0 double} {0×0 double} {0×0 double} {0×0 double}
{0×0 double} {0×0 double} {0×0 double} {0×0 double} {0×0 double}
{0×0 double} {0×0 double} {0×0 double} {0×0 double} {0×0 double}
Asad (Mehrzad) Khoddam
a is the cell array
b=find(cellfun(@(x) size(x,1)<3,a)==1);
while ~isempty(b)
a(b(1))=[];
b=b-1;
b(1)=[];
end
  1 个评论
Walter Roberson
Walter Roberson 2016-10-7
No, this checks for vectors less than 3 elements anywhere in the cell array.
The == 1 is redundant because the places that satisfy <3 will already return 1 and the other places will return 0 and find() automatically checks for non-zero. The code there is sort of like
find((x < 3) == true)
when you could just use
find(x < 3)

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