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Given a matrix A = [2 5 7; 4 1 8], write a for loop that will replace all the even numbers with 0.

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Sydney
Sydney 2016-10-7
回答： Andrei Bobrov 2016-10-7
I'm looking for something using a for loop (probably nested) and possibly mod(A,2) to determine the even numbers
What I tried: It took me a while to figure out how to format mod, but once I did I started with: for b=mod(A,2) I think tried to add a logical function (such as b==0) but it kept giving me errors. The closest thing that I could write that made sense in my head was:
for b=mod(A,2);
if b==0
A(b)=0
end
end
I would then get the error: Subscript indices must either be real positive integers or logicals.
I also couldn't figure out how to size a matrix to be the same size as a different matrix.
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Sydney
Sydney 2016-10-7
It took me a while to figure out how to format mod, but once I did I started with: for b=mod(A,2) I think tried to add a logical function (such as b==0) but it kept giving me errors. The closest thing that I could write that made sense in my head was:
% code
for b=mod(A,2);
if b==0
A(b)=0
end
end
I would then get the error: Subscript indices must either be real positive integers or logicals.
I also couldn't figure out how to size a matrix to be the same size as a different matrix.

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采纳的回答

Mohammad Haghighat
Mohammad Haghighat 2016-10-7
This can be a solution using for loops:
[m,n] = size(A);
for i = 1:m
for j = 1:n
if mod(A(i,j),2) == 0
A(i,j) = 0;
end
end
end
  2 个评论
James Tursa
James Tursa 2016-10-7
This is obviously a homework post. It is discouraged to do homework problems for others on this forum. Helping OP with concepts, correcting their code, etc is all within the spirit of this forum. But doing the entire problem outright for them is not.

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更多回答（1 个）

Andrei Bobrov
Andrei Bobrov 2016-10-7
A(rem(A,2)==0)=0;
or with loop
for ii = 1:numel(A)
if rem(A(ii),2) == 0
A(ii) == 0;
end
end

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