Error Masg Matrix Dimensions exceeded

Question

Ken 2016-10-8

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此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/306370-error-masg-matrix-dimensions-exceeded

回答： Image Analyst 2016-10-8

I am struggling over the above error msg. My code is below. Any hints app[reciated.

OptimalPath=zeros(40, 2);
iter=0;
M=1;
Row=1;
Col=1;
OptimalPath(M,1)=SearchSolution(SearchStart(1));
OptimalPath(M,2)=SearchSolution(SearchStart(2));
CurrentPos(M,1)=SearchSolution(SearchStart(1));
CurrentPos(M,2)=SearchSolution(SearchStart(2));
Min=SearchSolution(SearchStart(1),SearchStart(2));
while (Row < 8 & Col < 7)
 while not(SearchSolution(Row,Col) == 1)
   while not(SearchSolution(Row,Col) == 0)
  iter = iter+1;
    assert(maxIter>iter, 'maxIter assert triggered. Aborting.');
 for X=1:1:3
  for Y=1:1:3
 if Min>CurrentPos(M(1),M(2));
     Min=CurrentPos(M(1),M(2));
     Row=X;
     Col=Y; %capture the row and col corresp to the local min
   end
  end
 end
 CurrentPos(M,1)=Row;
 CurrentPos(M,2)=Col;
end
end
Row=Row+1;
Col=Col+1; 
M=M+1;
end

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Answer 1

Marc Jakobi 2016-10-8

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此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/306370-error-masg-matrix-dimensions-exceeded#answer_238122

编辑：Marc Jakobi 2016-10-8

在 MATLAB Online 中打开

This is causing your error:

if Min>CurrentPos(M(1),M(2));
     Min=CurrentPos(M(1),M(2));

M is a 1x1 matrix, so M(2) exceeds M's dimensions.

You probably mean

if Min>CurrentPos(M,2);
     Min=CurrentPos(M, 2);

or

if Min>CurrentPos(M,1);
     Min=CurrentPos(M, 1);

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Ken 2016-10-8

Tried both of the above but still get same error

Marc Jakobi 2016-10-8

编辑：Marc Jakobi 2016-10-8

Go through the code line for line and see where the error shows up. Refer to Image Analyst's links (answer below) if you are unsure how to debug. "Index exceeds matrix dimensions" is a very common error in Matlab that should be easy to find.

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Answer 2

Image Analyst 2016-10-8

1
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/306370-error-masg-matrix-dimensions-exceeded#answer_238159

在 MATLAB Online 中打开

Why are you saying this:

Row=X;
Col=Y; %capture the row and col corresp to the local min

This is opposite to the convention that the whole world uses.

You made the very common beginner mistake of thinking (x,y) = (row, column). It does not. If you're expecting (row, column), like you're indexing an array, then you need to use (y, x), NOT (x, y). Is that what you're doing? Take a very careful look at what your first index means and what you're passing in. If it's x, then pass in column. If it's row, then pass in y. Just make sure you're consistent.