Reducing the computation time using a for loop
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A is a matrix with a bigger size than the B matrix. B is a subset of A (except the last column that I am trying to fill A;s last column with the respective values of B's last column). I wrote the following loop that has been running for more than an hour although it should be simple. I hoe someone can help me to reduce the computation time:
for m=1:size(A,1)
for n=1:size(B,1)
x0a=A(:,2)==B(n,2) & A(:,1)==B(n,1);
if ~isempty(x0a)
A(m,end)=B(x0a,end);
end
end
end
采纳的回答
[isinB, Brow] = ismember(A(:, [1 2]), B(:, [1 2]), 'rows');
A(isinB, end) = B(Brow(isinB), end);
edit: silly typo
2 个评论
Danielle Leblance
2016-10-11
Guillaume
2016-10-11
You corrected my typo, but not correctly. The missing closing bracket was supposed to go at the end of B(:, [1 2]).
I've now fixed it in my answer.
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