how to write a very concise expression for matrix power

Xin
2016 10 12
2 个回答
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更新时间：2016 10 12
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I have a row vector, e.g. [1,2,3,4], and I want to put, say 3 different power [1;2;3] to create a matrix as follow:
[1,2,3,4]?^[1;2;3] = [1,2,3,4 ; 1,4,9,16 ; 1,8,27,64].
Anyone knows how to get it without using a loop. Many thanks!

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Matt J
Matt J 2016-10-12

1 个投票

As of R2016b, you can just do this
[1;2;3] .^ [1,2,3,4]
Otherwise, use bsxfun()

4 个评论
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Xin
Xin 2016-10-12
编辑：Xin 2016-10-12
Ahh, I am using 2011, didn't know it works in 2016.
Thanks for reply. Is there any other way to let it work.
Matt J
Matt J 2016-10-12
编辑：Matt J 2016-10-12
Upgrade!
Or, use bsxfun() as I suggested.
Xin
Xin 2016-10-12
Nice, bsxfun does work. Thank you so much!
dpb
dpb 2016-10-12
Then please ACCEPT the answer...

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更多回答（1 个）

dpb
dpb 2016-10-12

0 个投票

>> bsxfun(@power,[1:4],[1:3].')
ans =
1 2 3 4
1 4 9 16
1 8 27 64
>>

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Xin
Xin
2016-10-12

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dpb
dpb
2016-10-12

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