Strange issue encountered using textscan and cell arrays
1 次查看(过去 30 天)
显示 更早的评论
When I run the following snippet of code:
str = '(3.3940269999999999,1,0) (0,3.3940269999999999,0) (0,0,2.024902)';
format = '(%f, %d, %d) (%d, %f, %d) (%d, %d, %f)';
A = textscan(str, format);
matrix = [A{1,1}, A{1,4}, A{1,7} ; A{1,2}, A{1,5}, A{1,8}; A{1,3}, A{1,6}, A{1,9}]
I get the following output matrix =
3 0 0
1 3 0
0 0 2
Why were the floating point numbers converted to integers?
0 个评论
采纳的回答
Star Strider
2016-10-14
When I run a slightly modified version of your code (because format is a function that defines the format displayed in the Command Window and Tooltips), I get:
format_string = '(%f, %d, %d) (%d, %f, %d) (%d, %d, %f)';
A = textscan(str, format_string);
matrix =
3×3 int32 matrix
3 0 0
1 3 0
0 0 2
That is likely because of the '%d' format descriptors. Convert them to '%f':
format_string = '(%f, %f, %f) (%f, %f, %f) (%f, %f, %f)';
to get:
matrix =
3.394 0 0
1 3.394 0
0 0 2.0249
更多回答(1 个)
Eamon
2016-10-14
I think if you use the format function like below before the rest of your code, it will show the original floating point numbers.
format long
另请参阅
类别
在 Help Center 和 File Exchange 中查找有关 Data Type Conversion 的更多信息
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!