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Alternate for flipr command in matlab

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Bathrinath
Bathrinath 2012-3-1
Hi,
m = 3; n = 8; There are 8 elements in A
A = [33,47,44,49,40,21,45,48];
After sorting in descending order
A = [49,48,47,45,44,40,33,21]
I need final matrix
final =[ 49 48 47 ; 40 44 45 ; 33 21 ]
In first two rows 3 elemets has to be there.
In third row 2 elements has to be there,because n = 8.
Second row is printed in reverse order.
I cant use "flipr" in this case bcoz matrix is not same size.
Alternate rows has to be printed in reverse order.
Advice me regarding this.

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回答（2 个）

Walter Roberson
Walter Roberson 2012-3-1
You cannot create a numeric matrix which has different number of elements in various rows or columns. 8 elements cannot be arranged in to a 3-row numeric matrix -- not without adding an extra element.
Andrei Bobrov
Andrei Bobrov 2012-3-1
A = [33,47,44,49,40,21,45,48];
m = 3;
n = numel(A);
out = nan(m,ceil(n/m));
out(1:n) = sort(A,'descend');
out(:,2:2:end) = out(end:-1:1,2:2:end);
out = out'

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