Plotting a non-linear graph in Matlab
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Hi guys,
I have this equation f(g)=1+cos(g)*cosh(g)-a*g*(cos(g)*sinh(g)-sin(g)*cosh(g))=0. I am trying to plot it for (a,g).
I have the initial condition that when a=0 then g=1.8751.
I am not sure how to code it as an equation with two unknowns and two initial values ??
My suggestion would be to plot the graph by using the solve function by using a=a+da (where da is small increment of a) and using the previous value of g as an initial value to find g for the new value of a.
Regards, Rihab
3 个评论
Muhammad Usman Saleem
2016-10-15
编辑：Walter Roberson
2016-10-16
f(g)=1+cos(g)*cosh(g)-a*g*(cos(g)*sinh(g)-sin(g)*cosh(g))=0.
there are two equality sign in this equation write correct one plz
Rihab el-Wali
2016-10-15
Muhammad Usman Saleem
2016-10-15
good night, tomorrow will guide u in this regards
采纳的回答
Walter Roberson
2016-10-16
a = linspace(-4, 2); %the interesting part of the graph
g = zeros(size(a));
oldguess = 1.8751;
for K = 1 : length(a)
fa = @(g) 1+cos(g)*cosh(g)-a(K)*g*(cos(g)*sinh(g)-sin(g)*cosh(g));
this_g = fzero(fa, oldguess);
g(K) = this_g;
oldguess = this_g;
end
plot(a, g)
However, there are many solutions. You will, for example, get a different plot if you start with oldguess = 50
更多回答（1 个）
Star Strider
2016-10-15
编辑：Star Strider
2016-10-15
When in doubt, plot first:
[A,G] = meshgrid(-0.5:0.01:0.5, -20:0.1:20);
fga = @(a,g) 1+cos(g).*cosh(g)-a.*g.*(cos(g).*sinh(g)-sin(g).*cosh(g))
F = fga(A,G);
figure(1)
meshc(A, G, F)
grid on
There appear to be a possibly infinite number of solutions. Which one do you want?
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