How to use 'if' statement to pick up 3 to 4 values from the data that nearest to the mean?

Question

SyukriY 2016-10-16

0
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此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/307479-how-to-use-if-statement-to-pick-up-3-to-4-values-from-the-data-that-nearest-to-the-mean

评论： SyukriY 2016-10-16

采纳的回答： Walter Roberson

在 MATLAB Online 中打开

Hi, this question is on the same project I've been working on 10 Oct 2016 at 7:35.

I have 24 values of data and a mean value. I've been working to get 3 to 4 value from the last half of the data that are nearest to the mean by using 'if' statement. I know 'if' statement can be like these... [ if any(statement) ] or [ if all(statement) ] .

So, how can I code it to pick up 3 to 4 values from the data that nearest to the mean? Here is my code from the latest question.

function [Consistency,limit] = detection(x,y) 
H = x; 
G = H(y:24,:); 
limit = mean(H(1:24,:)); 
if all(G > limit) 
S = std(G); 
Consistency = S; 
else 
Consistency = inf; 
end

Hope anyone can guide me. Thanks.

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Answer 1

Walter Roberson 2016-10-16

1
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https://ww2.mathworks.cn/matlabcentral/answers/307479-how-to-use-if-statement-to-pick-up-3-to-4-values-from-the-data-that-nearest-to-the-mean#answer_239173

在 MATLAB Online 中打开

function [Consistency,limit] = detection(x,y) 
H = x; 
G = H(y:24,:); 
limit = mean(H(1:24,:));
vals4 = zeros(1,4);
bestdiff = inf(1,4);
bestvals = inf(1,4);
for r = 1 : size(G,1)
  for c = 1 : size(G,2)
    thisval = G(r,c);
    thisdiff = abs(thisval - limit);
    if thisdiff < bestdiff(1)
      bestdiff = [thisdiff, bestdiff(1), bestdiff(2), bestdiff(3)];
      bestvals = [thisval, bestvals(1), bestvals(2), bestvals(3)];
    elseif thisdiff < bestdiff(2)
      bestdiff = [bestdiff(1), thisdiff, bestdiff(2), bestdiff(3)];
      bestvals = [bestvals(1), thisval, bestvals(2), bestvals(3)];
    elseif thisdiff < bestdiff(3)
      bestdiff = [bestdiff(1), bestdiff(2), thisdiff, bestdiff(3)];
      bestvals = [bestvals(1), bestvals(2), thisval, bestvals(3)];
    elseif thisdiff < bestdiff(4)
      bestdiff = [bestdiff(1), bestdiff(2), bestdiff(3), thisdiff];
      bestvals = [bestvals(1), bestvals(2), bestvals(3), thisval];
    end
  end
end