i try to evaluate the initial value of an unknown I named x0 (5 * n + 1) with Uh Ah Ls Tvc Tb0 n x0(4*n)are data it
Undefined function 'x0' for input arguments of type 'double'.??
1 次查看(过去 30 天)
显示 更早的评论
Error in x0(5*n+1)=((Uh*Ah)/Ls)*((Tb0-x0(4*n))/log((Tvc-x0(4*n))/(Tvc-Tb0)));
采纳的回答
更多回答(0 个)
另请参阅
类别
在 Help Center 和 File Exchange 中查找有关 Characters and Strings 的更多信息
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!