Playing sound one after another, according to number inputed

Question

Valeria Chacon 2016-10-26

0
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此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/309188-playing-sound-one-after-another-according-to-number-inputed

评论： Massimo Zanetti 2016-10-27

if I have multiple sounds that already have specific tones and they're named: y0,y1,y2,y3,y4,y5,y6,y7,y8,y9

how can I make them play one after another without overlapping? the input is random so if the user types in:1,2,3,4 then the sounds y1,y2,y3,and y4 should be played one after the other. Thank you!

[Merged from duplicate question]

     prompt = 'Enter atleast 10 numbers: ';
     str='0';
     while length(regexp(str,'\d'))~=10
  str = input(prompt,'s');
     end
     N=length(str);
     count=1;
     for k=1:N
         m=str2double(str(k));
         if isnan(m)==0
             str(count)=k;
             count=count+1;
             numbers = cell2mat(sscanf((str),'k'))
         disp(m)
         end
     end
%sound 1 
      fs=8192;
      T=.5; 
      t=0:(1/fs):T;
      y1=cos(2*pi*1209*t)+cos(2*pi*697*t);
      sound(y1,fs);
      pause(.5);
%sound 2
      fs=8192;
      T=.5; 
      t=0:(1/fs):T;
      y2=cos(2*pi*1336*t)+cos(2*pi*697*t);
      sound(y2,fs);
      pause(.5);
%sound 3
      fs=8192;
      T=.5; 
      t=0:(1/fs):T;
      y3=cos(2*pi*1477*t)+cos(2*pi*697*t);
      sound(y3,fs);
      pause(.5);
%sound 4
      fs=8192;
      T=.5; 
      t=0:(1/fs):T;
      y4=cos(2*pi*1209*t)+cos(2*pi*770*t);
      sound(y4,fs);
      pause(.5);
%sound 5
      fs=8192;
      T=.5; 
      t=0:(1/fs):T;
      y5=cos(2*pi*1336*t)+cos(2*pi*770*t);
      sound(y5,fs);
      pause(.5);
%sound 6
      fs=8192;
      T=.5; 
      t=0:(1/fs):T;
      y6=cos(2*pi*1477*t)+cos(2*pi*770*t);
      sound(y6,fs);
      pause(.5);
%sound 7
      fs=8192;
      T=.5; 
      t=0:(1/fs):T;
      y7=cos(2*pi*1209*t)+cos(2*pi*852*t);
      sound(y7,fs);
      pause(.5);
%sound 8
      fs=8192;
      T=.5; 
      t=0:(1/fs):T;
      y8=cos(2*pi*1336*t)+cos(2*pi*852*t);
      sound(y8,fs);
      pause(.5);
%sound 9
      fs=8192;
      T=.5; 
      t=0:(1/fs):T;
      y9=cos(2*pi*1477*t)+cos(2*pi*852*t);
      sound(y9,fs);
      pause(.5);
%sound 0
      fs=8192;
      T=.5; 
      t=0:(1/fs):T;
      y0=cos(2*pi*1336*t)+cos(2*pi*941*t);
      sound(y0,fs); 
  pause(.5);

this is my whole code and I'm having trouble figuring out how I can get one sound to play after the other depending on what the user inputs so if the user inputs: 4560987321 then I want it to play the sounds in order (y4,y5,y6,y0,y9,y8,y7,y3,y2,y1) thank you!

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Answer 1

Star Strider 2016-10-26

3
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https://ww2.mathworks.cn/matlabcentral/answers/309188-playing-sound-one-after-another-according-to-number-inputed#answer_240830

You need to use the playblocking function to prevent them from overlapping. This is part of the audioplayer functions, so you should have access to it. See the documentation for details.

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Answer 2

Massimo Zanetti 2016-10-26

1
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/309188-playing-sound-one-after-another-according-to-number-inputed#answer_240774

编辑：Massimo Zanetti 2016-10-26

在 MATLAB Online 中打开

Just compute the time T (secs) the file lasts by using sample rate information and number of samples. Then, pause the for loop for the number of seconds (plus 1 if you want delay time of 1 sec. in between). For randomness, arrange files in array and randomize on indeces:

s(1)=load('gong.mat','y','Fs');
s(2)=load('handel.mat','y','Fs');
randsel = randperm(numel(s));
for x=s(randsel)
    sound(x.y,x.Fs);
    T = numel(x.y)/x.Fs;
    pause(T+1);
end