5 point asymmetric moving average using past values
3 次查看(过去 30 天)
显示 更早的评论
Hello everyone, and thank you in advance for taking the time to inspect my question.
I am currently working on a code that will allow me to take a signal and apply a 5-point asymmetric moving average filter (Past Values) to it. In an attempt to do that, I have written the following code:
N = length(ECG); %The number of rows in the columns of the ECG data: Both columns contain 1040 rows
A = ECG(:,2); %The second column of the ECG data specifies amplitude
time = ECG(:,1); %The first column of the ECG data specifies the time point
for i = 5 : (N) %Sets a counter
asym5p(i)= mean(A(i-4:i)); %Creates a vector from the mean of the four previous terms & the term of interest
end
plot (time (5 : (N)), asym5p, 'm') %Plots the vector with time on the x-axis and voltage on the y-axis
xlabel('Time (sec)');
ylabel('Amplitude (Volts)');
title('5 Point Asymmetric Filter (Future)');
Despite my best efforts, I cannot understand why the code will not compile, as I keep receiving the error message "Vectors must be the same length."
Any insight into this would be greatly appreciated.
Regards,
Luke Pretzie
0 个评论
采纳的回答
Swarooph
2016-10-26
Looks like when you are plotting, size of asym5p is 1x1040 while size of time (5 : (N)) is 1x1036. These need to be same length for plot to work. For e.g. if I change the following line
plot (time (5 : (N)), asym5p, 'm')
to the following line
plot (time , asym5p, 'm')
The code will work.
P.S: I generated ECG data as follows to run your code. For the future, consider attaching the data or provide the sample inputs for easy replication of code behavior.
ECG = rand(1040,2);
更多回答(0 个)
另请参阅
类别
在 Help Center 和 File Exchange 中查找有关 Applications 的更多信息
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!