Found the answer. Thanks
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Found the answer. Thanks
1 个评论
James Tursa
2016-10-26
编辑：James Tursa
2016-10-26
Please post a short example for us so we know what exactly you are trying to do. E.g., post a small example input matrix and then post the result(s) you would be expecting. Note that trying to name variables x1, x2, etc in a loop fashion is not a good idea.
回答（1 个）
James Tursa
2016-10-26
Do you mean like this?
[rows cols] = size(a);
nDiags = rows + cols - 1;
b=fliplr(a);
x = zeros(min(rows,cols),nDiags);
for i=1:nDiags
d = diag(b,cols-i);
x(1:numel(d),i)=d;
end
Produces:
>> a
a =
1 2 3 4 5
12 -4 9 11 83
2 4 6 8 24
64 0 21 33 11
104 63 16 72 76
>> x
x =
1 2 3 4 5 83 24 11 76
0 12 -4 9 11 8 33 72 0
0 0 2 4 6 21 16 0 0
0 0 0 64 0 63 0 0 0
0 0 0 0 104 0 0 0 0
1 个评论
James Tursa
2016-10-26
OK, how about this?
[rows cols] = size(a);
nDiags = rows + cols - 1;
b=fliplr(a);
c = cell(nDiags,1);
for i=1:nDiags
c{i} = diag(b,cols-i);
end
x = vertcat(c{:})';
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2016-10-26
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