Info

此问题已关闭。 请重新打开它进行编辑或回答。

how to play sound one after the other depending on the number inputed

1 次查看(过去 30 天)
prompt = 'Enter atleast 10 numbers: ';
str='0';
while length(regexp(str,'\d'))~=10
str = input(prompt,'s');
end
N=length(str);
count=1;
for k=1:N
m=str2double(str(k));
if isnan(m)==0
str(count)=k;
count=count+1;
numbers = cell2mat(sscanf((str),'k'))
disp(m)
end
end
%sound 1
fs=8192;
T=.5;
t=0:(1/fs):T;
y1=cos(2*pi*1209*t)+cos(2*pi*697*t);
sound(y1,fs);
pause(.5);
%sound 2
fs=8192;
T=.5;
t=0:(1/fs):T;
y2=cos(2*pi*1336*t)+cos(2*pi*697*t);
sound(y2,fs);
pause(.5);
%sound 3
fs=8192;
T=.5;
t=0:(1/fs):T;
y3=cos(2*pi*1477*t)+cos(2*pi*697*t);
sound(y3,fs);
pause(.5);
%sound 4
fs=8192;
T=.5;
t=0:(1/fs):T;
y4=cos(2*pi*1209*t)+cos(2*pi*770*t);
sound(y4,fs);
pause(.5);
%sound 5
fs=8192;
T=.5;
t=0:(1/fs):T;
y5=cos(2*pi*1336*t)+cos(2*pi*770*t);
sound(y5,fs);
pause(.5);
%sound 6
fs=8192;
T=.5;
t=0:(1/fs):T;
y6=cos(2*pi*1477*t)+cos(2*pi*770*t);
sound(y6,fs);
pause(.5);
%sound 7
fs=8192;
T=.5;
t=0:(1/fs):T;
y7=cos(2*pi*1209*t)+cos(2*pi*852*t);
sound(y7,fs);
pause(.5);
%sound 8
fs=8192;
T=.5;
t=0:(1/fs):T;
y8=cos(2*pi*1336*t)+cos(2*pi*852*t);
sound(y8,fs);
pause(.5);
%sound 9
fs=8192;
T=.5;
t=0:(1/fs):T;
y9=cos(2*pi*1477*t)+cos(2*pi*852*t);
sound(y9,fs);
pause(.5);
%sound 0
fs=8192;
T=.5;
t=0:(1/fs):T;
y0=cos(2*pi*1336*t)+cos(2*pi*941*t);
sound(y0,fs);
pause(.5);
this is my whole code and I'm having trouble figuring out how I can get one sound to play after the other depending on what the user inputs so if the user inputs: 4560987321 then I want it to play the sounds in order (y4,y5,y6,y0,y9,y8,y7,y3,y2,y1) thank you!

回答(0 个)

此问题已关闭。

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by