Replace efficiently values in matrix without for-loops
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Hi, This is my problem. Suppose you have a vector b:
b=[234 786 674 23];% the values are chosen at random for this example
and a matrix A:
A=[2 1;
4 4]; %the value of the elements of A should be <=length(b)
it exists a method or a function to obtain a second matrix B of the same dimensions of A but with the values replaced by the corresponding value in b?? For the previous example:
B=[786 234;
23 23]; % i.e., B(i,j)=b(A(i,j))
this is easily to do with at least one for-loop. but I am looking for a function or method that does this without for loops, maybe in a vectorized way (thus in an efficient way)!
Can someone help me??
Thank you,
Matteo
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更多回答（2 个）
the cyclist
2012-3-2
Simple and elegant:
b(A)
Jonathan Sullivan
2012-3-2
B = b(A);
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