Why WHILE loop doesn't advance?
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function cam()
clc
clear all
close all
N_i = input('N de intervalos:');
k=1;
while(k<=N_i)
k
beta_i(k) = input('Beta do intervalo:');
L(k) = input('Lift do intervalo:');
mov(k) = input('Movimento do intervalo:');
k=k+1;
end
R_0 = input('Raio base:');
tb_i=0;
tb_f=1;
teta=0;
passo=1;
n=1;
T(n)=teta;
j=1;
while(j<=N_i)
j
switch mov(j)
case 1
while(teta<=beta_i(j))
y=0.5*L(j)*(1-cos(pi*teta/beta_i(j)));
dy=((pi*L(j))/(2*beta_i(j)))*sin(pi*teta/beta_i(j));
u=(R_0+y)*sin(teta)+dy*cos(teta);
v=(R_0+y)*cos(teta)-dy*sin(teta);
T(n)=teta;
A(n,:,j)=[y,dy,j]
P(n,:,j)=[u,v,j]
n=n+1;
teta=teta+passo;
end
case 2
while(teta<=beta_i(j))
y=L(j)*((teta/beta_i(j))-sin(2*pi*(teta/beta_i(j))));
dy=(L(j)/beta_i(j))*(1-cos(2*pi*(teta/beta_i(j))));
u=(R_0+y)*sin(teta)+dy*cos(teta);
v=(R_0+y)*cos(teta)-dy*sin(teta);
T(n)=teta;
A(n,:,j)=[y,dy,j]
P(n,:,j)=[u,v,j]
n=n+1;
teta=teta+passo;
end
end
j=j+1;
end
end
Why the "while(j<=N_i)" loop only computes A and P for j=1 and doesn't advance after that? Can't understand...
5 个评论
Adam
2016-11-1
Well, for a start we have no idea what N_i is since it is a user input.
Miguel Viegas Leal
2016-11-1
Miguel Viegas Leal
2016-11-1
Image Analyst
2016-11-1
Can you give typical numbers for all 5 user inputs, not just one, so we know what to enter and can try your code?
Miguel Viegas Leal
2016-11-1
采纳的回答
Walter Roberson
2016-11-1
1 个投票
I notice that you do not initialize teta between the two iterations of the while loop. Your while test is based upon teta which is going to continue to have the value it had after the first iteration of the loop, so the end condition might already be satisfied.
更多回答（1 个）
Image Analyst
2016-11-1
It worked for me:
N de intervalos:2
k =
1
Beta do intervalo:3
Lift do intervalo:3
Movimento do intervalo:4
k =
2
Beta do intervalo:5
Lift do intervalo:6
Movimento do intervalo:7
Raio base:0
j =
1
j =
2
3 个评论
Miguel Viegas Leal
2016-11-1
Image Analyst
2016-11-1
That also does both j. Look:
N de intervalos:2
k =
1
Beta do intervalo:180
Lift do intervalo:3
Movimento do intervalo:1
k =
2
Beta do intervalo:90
Lift do intervalo:2
Movimento do intervalo:2
Raio base:0.025
j =
1
j =
2
Miguel Viegas Leal
2016-11-1
编辑：Miguel Viegas Leal
2016-11-1
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