If I have a matrix of 100 rows by 5 columns, how can I make it a 1 row x 500 column matrix, where each row (1x5) is placed one after the other to make a 1x500 matrix?

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Eric
Eric 2016-11-2
回答： Eric 2016-11-3
[r,c] = size(data);%(100 rows by 5 columns)
datanew = zeros(1,500)%
for i = 1:r
startcol = (1+(i-1)*5);
endcol = (5*i);
datanew(1,data(1,startcol:endcol)); %I get an error "Subscript indices must either be real positive integers or logicals." But data(1,startcol:endcol) does contain the correct 1x5 data, therefore, uncertain why the error.
end

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采纳的回答

James Tursa
James Tursa 2016-11-2
datanew = reshape(data',1,[]);

更多回答（3 个）

Mischa Kim
Mischa Kim 2016-11-2
Use the reshape command.
Nick Counts
Nick Counts 2016-11-2
编辑：Nick Counts 2016-11-2
You can use reshape:
A = randi(10,100,5)
B = reshape(A,1,500)
  • A will be a 100x5 matrix
  • B will be a 500x1 matrix
As to your particular error, I am not certain. Your code doesn't work as posted because data isn't defined. So I can't say what's going on. If you want to post some additional code, we can take a look at what's going on and help you find the issue.
  1 个评论
Nick Counts
Nick Counts 2016-11-2
If you were trying to do this inside a for-loop, you can use horizcat or vertcat. You could also use indexing tricks, but your calculation of startcol and endcol seems to be broken. Easier to go row by row.
data = randi(10,100,5)
newData = []
for i = 1:length(data)
newData = vertcat(newData, data(i,:)');
end
I believe James's reshape is what you're really looking for

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Eric
Eric 2016-11-3
I appreciate all the suggestions.

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