Index exceeds matrix dimensions.

1 次查看（过去 30 天）
Aldo
Aldo 2016-11-4
回答： Alexandra Harkai 2016-11-4
f21=@(x)(exp(-x/3))/(4-cos(pi*x));
n=25; h=2.5/n; t=h*(0:n); f=f21(t).^2; T26=pi*h*(sum(f)-(f(1)+f(n+1))/2);
n=52; h=2.5/n; t=h*(0:n); f=f21(t).^2; T52=pi*h*(sum(f)-(f(1)+f(n+1))/2);
Can't figure why Index is exceeding the matrix dimensions. Since the graph goes up to 5.

请先登录，再回答此问题。

采纳的回答

Alexandra Harkai
Alexandra Harkai 2016-11-4
Did you check what you get for f?
f21=@(x)(exp(-x/3))/(4-cos(pi*x));
This returns a scalar, so f will be of size 1*1. If you want element-wise division, then this will not fail:
f21=@(x)(exp(-x/3))./(4-cos(pi*x));

更多回答（0 个）

类别

在 Help Center 和 File Exchange 中查找有关 Matrix Indexing 的更多信息

标签

尚未输入任何标签。

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by