How to remove MSB bit from a binary number?
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suppose i have an cell array 'c' of 1*256 size.
let c(1)=10010000
i want
p1= 10010000;
p2=0010000;
p3=010000;
p4=10000;
p5=0000;
p6=000;
p7=00;
p8=0;
it means in each step the MSB should be removed.. Thank you..plz any body suggest...
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Walter Roberson
2016-11-8
cellfun(@(b) arrayfun(@(idx) b(idx:end), 1:length(b), 'uniform', 0), c, 'uniform', 0)
4 个评论
Walter Roberson
2016-11-9
That is what my first code does provided you start with cell array of string
更多回答(1 个)
Guillaume
2016-11-9
b = imresize(imread('f.jpg'), [16 1]);
d = arrayun(@(s) bitshift(b, -s), 1:8, 'UniformOutput', false);
d{1} is all the values of b shifted by 1 bit, d{2} is all the values of b shifted by 2 bits, ... d{8} is all the values of b shifted by 8 bits.
There is absolutely no point in converting numbers in strings of 0 and 1 to manipulate bits Computers are much better at manipulating bits of numbers than they are at manipulating characters of strings.
You can always convert the d{i} to strings if you really wish to.
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