Cell array in a loop

Question

gsourop 2016-11-9

0
链接

此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/311377-cell-array-in-a-loop

评论： Mostafa 2016-11-13

Hi everyone,

I have created a cell array of dimensions 1x10, named A. Each element contains a 100x5 matrix. Hence, I got 10 matrices 100x5. However, I want to put every matrix of the cell array into a loop. If Bis a 100x5 matrix, the loop should look like:

for t=1:100;
j=1:5;
x=B(t,j)-A(t,j)
end;
end;

At the end x should deliver a 1x10 cell array that will contain 10 elements of matrices 100x5.

I would appreciate any help. Thank you in advance!

0 个评论
显示 -2更早的评论隐藏 -2更早的评论

请先登录，再进行评论。

请先登录，再回答此问题。

Answer 1

Mostafa 2016-11-9

0
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/311377-cell-array-in-a-loop#answer_242588

编辑：Mostafa 2016-11-9

在 MATLAB Online 中打开

% B is already defined, a matrix of doubles
% A is already defined, a cell array of matrices
% B and the matrices in A have the same size
x = cellfun(@(X) B - X, A, 'UniformOutput', 0);

6 个评论
显示 4更早的评论隐藏 4更早的评论

Mostafa 2016-11-9

在 MATLAB Online 中打开

You missed a bracket somewhere so I don't know do what you want this to evaluate to

x=c*inv((B(t,j)-A(t,j))*((B(t,j)-A(t,j))')*(A(t,j)-C(t,1)*ones(1,5));

In any case, what cellfun does is that it loops on a cell array and applies the same function to all the elements in it. In your case, each element is a 100x5 matrix. It can be also written as this:

for i = 1:length(A)
  x{i} = B - A{i};
end
%Since A is a cell and we need to address the data inside, we used A{i}

Matlab can evaluate a summation or subtraction of two matrices when they have the same size, and can do multiplication when the inner dimensions agree (100x5 * 5x100). What you can also do, is to multiply each element in the matrix to the corresponding one in the next matrix using the .* notation.

%For example: 
x = cellfun(@(X) B.*X, A, 'UniformOutput', 0);
%Let's say you want to evaluate this:
C2 = = C*ones(1,5);
x = cellfun(@(X) c*inv((B-X)*((B-X)'))*(X-C2), A, 'UniformOutput', 0);

As you can see, using cellfun doesn't change the notation that much. You need to identify the cell array (X) and write it in the equation as X, then pass it as the second argument to the cellfun.

%So basically
cellfun(@(Variable) Variable*2, CellArray, 'UniformOutput', 0);

Guillaume 2016-11-10

While preallocation is indeed advisable, my main reason for creating x beforehand was actually to demonstrate that cellfun creates an output the same shape as the input. Without that preallocation, the output is a row vector.

The problem with length is that you open yourself to bugs if in the future the input changes from vector to multidimensional. The above is a perfect example: if the input is a matrix instead of a vector, your loop will only process the first X elements of the ND cell array, where X is the size of the largest dimension.

My version with numel works with any shape and any number of dimensions.

For that reason, I never use length. If I want to operate over all the elements of the inputs (regardless of shape), I use numel. If I want to operate over a particular dimension, I use size with the dimension specified.

Mostafa 2016-11-13

I'm not arguing with your point, I'm saying that it's a personal preference in case of 1-D arrays (which was the case in the fore mentioned example). In my codes, whenever I see length, I immediately understand that I'm dealing with an array - not a matrix or an input of unspecified size.

I totally agree that the general form is to use numel, or even better: cellfun

请先登录，再进行评论。