I want to copy the rows of G1 to G2 in inner for loop but error occurs , please help

Question

Junaid Khan 2016-11-13

0
链接

此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/311973-i-want-to-copy-the-rows-of-g1-to-g2-in-inner-for-loop-but-error-occurs-please-help

编辑： Walter Roberson 2016-11-14

G1 = [1     1     1     1     1     1     1     1     1     1     1     1     1     1     1     1;
     0     0     0     0     0     0     0     0     1     1     1     1     1     1     1     1;
     0     0     0     0     1     1     1     1     0     0     0     0     1     1     1     1;
     0     0     1     1     0     0     1     1     0     0     1     1     0     0     1     1;
     0     1     0     1     0     1     0     1     0     1     0     1     0     1     0     1;
     0     0     0     0     0     0     0     0     0     0     0     0     1     1     1     1;
     0     0     0     0     0     0     0     0     0     0     1     1     0     0     1     1;
     0     0     0     0     0     0     1     1     0     0     0     0     0     0     1     1;
     0     0     0     0     0     0     0     0     0     1     0     1     0     1     0     1;
     0     0     0     0     0     1     0     1     0     0     0     0     0     1     0     1;
     0     0     0     1     0     0     0     1     0     0     0     1     0     0     0     1];
m=4;
r=4;
k=0;
n=2^m;
k=15;
for a=r:-1:2
    M=factorial(m)/(factorial(m-a)*factorial(a));
    G2 = zeros(M,n);
    for o=1:1:M
       G2(o,:) = G1(k,:);
       k=k-1;
    end
end

0 个评论
显示 -2更早的评论隐藏 -2更早的评论

请先登录，再进行评论。

请先登录，再回答此问题。

Answer 1

Daniel kiracofe 2016-11-13

0
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/311973-i-want-to-copy-the-rows-of-g1-to-g2-in-inner-for-loop-but-error-occurs-please-help#answer_243112

the first time through the loops, k = 15. but size(G1) is 11x16. So the first time you are effectively doing

G2(o,:) = G1(15,:)

which doesn't work. Maybe you meant this instead?

G2(:, o) = G1(:,15)

2 个评论
显示无隐藏无

Junaid Khan 2016-11-13

This this the complete code, value of a decrease , M is computed and G2 is generated having rows equal to M, than i want to copy G1 rows portion to G2 in each iteration of for loop, the complete code is given below G1 = [1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1; 0 0 0 0 0 0 0 0 1 1 1 1 1 1 1 1; 0 0 0 0 1 1 1 1 0 0 0 0 1 1 1 1; 0 0 1 1 0 0 1 1 0 0 1 1 0 0 1 1; 0 1 0 1 0 1 0 1 0 1 0 1 0 1 0 1; 0 0 0 0 0 0 0 0 0 0 0 0 1 1 1 1; 0 0 0 0 0 0 0 0 0 0 1 1 0 0 1 1; 0 0 0 0 0 0 1 1 0 0 0 0 0 0 1 1; 0 0 0 0 0 0 0 0 0 1 0 1 0 1 0 1; 0 0 0 0 0 1 0 1 0 0 0 0 0 1 0 1; 0 0 0 1 0 0 0 1 0 0 0 1 0 0 0 1]; m=4; r=4; k=0; n=2^m; for i=1:r k= k+factorial(m)/(factorial(m-i)*factorial(i));

end

for a=r:-1:2 M=factorial(m)/(factorial(m-a)*factorial(a)); G2 = zeros(M,n); for o=M:1:1 G2(o,:) = G1(k,:); k=k-1; end end

Daniel kiracofe 2016-11-13

That doesn't change anything about my previous comment. at the conclusion of this section of the code

for i=1:r k= k+factorial(m)/(factorial(m-i)*factorial(i)) end

the variable k has the value 15. And G1 has size 11x16 = 11 rows and 16 columns.. So G1(k,:) is asking to access the 15th row of a matrix that has only 11 rows. You can't copy a row that doesn't exist.

请先登录，再进行评论。