bsxfun with AND condition

AA
2016 11 15
2 个回答
回答已采纳
更新时间：2017 2 4
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0 个投票

How can I use a code to see if compare1<q{x,y}<compare2
Basically the lt/gt function combined with an and function?
bsxfun(@lt,q{x,y},compare2 & q{x,y},compare1);

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James Tursa
James Tursa 2016-11-15
编辑：James Tursa 2016-11-15

0 个投票

Assuming q{x,y} and compare# are different sizes and need bsxfun, just & the two separate calculations:
result = bsxfun(@lt,compare1,q{x,y}) & bsxfun(@lt,q{x,y},compare2);
For R2016b you would not need bsxfun for this at all but could code the < operations directly.

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AA
AA 2017-2-3

0 个投票

no it doesnt work. it gives me one set that is less than compare 2 and another set that is less than compare 1. after that it combines these two sets.
I need compare1<q{x,y}<compare2

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James Tursa
James Tursa 2017-2-4
Please post your code so we know what "... doesn't work ..." means to you.

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