Finding element in java LinkedList
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Is there a way to get index of any vector+the vector, that has 1 on first index and 2 on second index? So in this case it would return [1 2 3 4] and 1. So I can remove it after, when for example last digit is 4...(Trying to implement DFS AI method for solving the decanting puzzle, could do it without linked list, but using linkedlist would make it more fun for me to write...)
open = java.util.LinkedList;
open.add([1 2 3 4]);
open.add([2 3 4 5]);
2 个评论
Geoff Hayes
2016-11-16
Jakub - open is a built-in MATLAB function name, so you may want to rename your above variable to avoid conflicting with this function.
Also, please clarify what you mean by ...vector+the vector... Are you adding the two vectors? How does this example return both [1 2 3 4] and 1?
Jakub Matousek
2016-11-16
编辑：Jakub Matousek
2016-11-16
采纳的回答
Geoff Hayes
2016-11-17
Jakub - if you just want to compare each element in your linked list to a specific array, checking to see if the first n elements match those of the array, then you could try something like
myList = java.util.LinkedList;
myList.add([1 2 3 4]);
myList.add([2 3 4 5]);
myList.add([1 2 3 4 5 6 7 8]);
myList.add([1 2]);
myList.add([1 2 3]);
dataToCompare = [1 2 3]';
for k=0:myList.size() -1
element = myList.get(k);
if length(element) >= length(dataToCompare)
if all(element(1:length(dataToCompare)) == dataToCompare)
fprintf('Found a match at %d!\n',k);
end
end
end
The output for the above would be
Found a match at 0!
Found a match at 2!
Found a match at 4!
indicating a match on the [1 2 3].
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