Help with Newton's method function?
9 次查看(过去 30 天)
显示 更早的评论
This is the function I've been making to run Newton's method, but I can't get it to work. Any help with what I might be missing? Thanks!
function xn = newtonmethod(f,fd,x0,tol)
xn=x0;
err=abs(f(xn)-0);
i=0;
while err>tol
i=i+1;
xnew=xn-(f(xn)/fd(xn));
err=abs(f(xnew)-0);
end
0 个评论
回答(1 个)
Walter Roberson
2016-11-20
I suspect your
err=abs(f(xnew)-0);
should be
err=abs(f(xnew)-f(xn));
unless you know that your f() has a "right" value of 0.
另请参阅
类别
在 Help Center 和 File Exchange 中查找有关 Loops and Conditional Statements 的更多信息
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!