algorithm to code conversion
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how to convert the below algorithm to code
algorithm is :
search feasible solution on constraints c(n)
if a feasible solution is found then
c1=0 c2=n
while c1-c22<=0 do
c=(c1+c2)/2
search a feasible solution on constraints c(i)
if a feasible solution is found then
c2=c
else
c1=c
end
end
else
the algorithm cannot obtain any solution is the planning period
end
1 个评论
Walter Roberson
2016-11-22
http://www.mathworks.com/matlabcentral/answers/29922-why-your-question-is-not-urgent-or-an-emergency
Please do not keep tagging your posts as "important". You get the same priority that every else does, which is "whenever someone is awake and feels like answering the question".
回答（2 个）
DR Somashekar R
2021-12-10
0 个投票
INPUT: S, a 2D grayscale image.
OUTPUT: H 0 , H 1 , and H 2 .
H 0 = PDT(S)
Add a border on top and bottom of S, called S̃ 1
Add a border on the left and right of S, called S̃ 2
Add borders to all 4 sides of S, called S̃ 3
H 1,1 = PDT( S̃ 1 ) and H 1,2 = PDT( S̃ 2 )
H 1 = H 1,1 + H 1,2 − 2H 0
H 2 0 = PDT( S̃ 3 )
H 2 = H 2 0 − H 1 − H 0
return H 0 , H 1 , H 2
2 个评论
DR Somashekar R
2021-12-10
I need matlab code for this algorithm
Can any one help please
Walter Roberson
2021-12-11
See padarray() for adding borders.
I have no idea what PDT() is.
Manish Sharma
2022-4-26
0 个投票
//defining 5 dominant rays
for rayout � 1: 5 do
//defining horizontal angles
for hori � −180: 180° do
//defining vertical angles
for vert � −90: 90° do
//developing rays and increment
rayout[i] � 1
Develop-ray � i+1
hori �� > verti
//finding intersection points
while rayout � intersect do
for j � 1: 2 do
//finding diffracted rays
if difrout � 1 then
raydfr � raydfr + 1
else
end
//finding refracted rays
rays � rayrefr
rayrefr � rayrefr + 1
end
end
end
//applying the proposed model
PLCI(d)[dB] � FSPL(f, d0) + 10n. log(d/d0) + XCI
σSF
end
end
end
2 个评论
Walter Roberson
2022-4-26
Unfortunately some of the characters did not come through.
Walter Roberson
2022-4-26
difrout is not defined.
The variables involved in your while loop do not appear to be changed in the loop, which would lead to an infinite loop.
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2022-4-26
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