question on using parfor

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Baozai
Baozai 2016-11-22
评论： Alexandra Harkai 2016-11-24
Hello, all.
I got a question on using parfor in matlab. When I tried to run the following code, I got an error showing:"Error: The variable Resp in a parfor cannot be classified.". Is this because Resp will be generated simultaneously when jjjj will be executed parallelly? If so, does this mean I can not perform this since different Phi use the same Resp as the first structure name? Will there be any idea on solving this problem? Thank you very much.
The following are the codes:
sizePhiValuep = 7;
sizeMassp = 20;
parfor (jjjj=1:sizePhiValuep,7)
Resp.(sprintf('Phi%d',jjjj)).MaxX2RespBegin_beta= zeros(sizeMassp,1);
Resp.(sprintf('Phi%d',jjjj)).MaxX2RespEnd_beta= zeros(sizeMassp,1);
end

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采纳的回答

Alexandra Harkai
Alexandra Harkai 2016-11-22
The error message refers to the variable classification when using parfor: classification-of-variables-in-parfor-loops. It doesn't know if you'll operate on segments in each loop or accumulate values regardless of the iteration order.
You could make Resp-something an array (or two arrays, if you need Begin and End) and index into that from the corresponding loop using jjjj.

更多回答（1 个）

Baozai
Baozai 2016-11-23
Thank you, Alexandra, When I change the code to the following, it works.
sizePhiValuep = 7;
sizeMassp = 20;
parfor (jjjj=1:sizePhiValuep,7)
Resp(jjjj).Phi.MaxX2RespBegin_beta= zeros(sizeMassp,1);
Resp(jjjj).Phi.MaxX2RespEnd_beta= zeros(sizeMassp,1);
end
  1 个评论
Alexandra Harkai
Alexandra Harkai 2016-11-24
Cool.
Dynamic variable name generation for indexing purposes ( sprintf('Phi%d',jjjj) ) should be avoided anyway, so it's always good practice to use 'actual' indexing instead.

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