HELP with TICTACTOE code

Question

Charly Perez 2016-11-25

2
链接

此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/313999-help-with-tictactoe-code

评论： Sidhant 2022-11-24

I need help determining the winner it only reads the winner if its crisscross.

Here is what I have:

clear all
clc
close all
board = zeros(3,3);
% Draw Board
figure
plot([.5 3.5],[-1.5 -1.5], 'k','linewidth',2);
hold on
plot([.5 3.5],[-2.5 -2.5], 'k','linewidth',2)
plot([1.5 1.5],[-.5 -3.5], 'k','linewidth',2)
plot([2.5 2.5],[-.5 -3.5], 'k','linewidth',2)
hold off
axis off
% Obtain first move
move = input('enter player 1 move [r,c] ');
r = move(1);
c = move(2);
board(r,c) = 1;
text(c,-r,'X','horizontalalignment','center','fontsize',20)
% Start loop with 2nd player
for turn = 1:4
    move = input('enter player 2 move [r,c] ');
    r = move(1);
    c = move(2);
    board(r,c) = -1;
    text(c,-r,'O','horizontalalignment','center','fontsize',20)
      % Check for victory by 0, 2nd player
      result = [sum(board), sum(board) ];
      result(1) = board(1,1) + board(2,2) + board(1,3);
      result(2) = board(2,1) + board(2,2) + board(2,3);
      result(3) = board(3,1) + board(3,2) + board(3,3);
      result(4) = board(1,1) + board(2,1) + board(3,1);
      result(5) = board(2,1) + board(2,2) + board(2,3);
      result(6) = board(1,3) + board(2,3) + board(3,3);
      result(7) = board(1,1) + board(2,2) + board(3,3);
      result(8) = board(1,3) + board(2,2) + board(3,1);
      if any(result == -3)
          disp('player 2 wins')
          break
      end
      % Repeat for player 1
      move = input('enter player 1 move [r,c] ');
      r = move(1);
      c = move(2);
      board(r,c) = 1;
      text(c,-r,'X','horizontalalignment','center','fontsize',20)
      % Check for victory for X, 1st player
      result = [sum(board), sum(board) ];
      result(1) = board(1,1) + board(2,2) + board(1,3);
      result(2) = board(2,1) + board(2,2) + board(2,3);
      result(3) = board(3,1) + board(3,2) + board(3,3);
      result(4) = board(1,1) + board(2,1) + board(3,1);
      result(5) = board(2,1) + board(2,2) + board(2,3);
      result(6) = board(1,3) + board(2,3) + board(3,3);
      result(7) = board(1,1) + board(2,2) + board(3,3);
      result(8) = board(1,3) + board(2,2) + board(3,1);
      if any(result == 3)
          disp('player 1 wins')
          break
      end
  end
  % Checks for draw
  if all(result ~= 3) & (sum(sum(abs(board))) == 9)
      disp('nobody wins')
  end

4 个评论
显示 2更早的评论隐藏 2更早的评论

Ansil Thekkekkara 2022-5-11

How do we enter the input?

Sidhant 2022-11-24

clear all

clc

close all

board = zeros(3,3);

% Draw Board

figure

plot([.5 3.5],[-1.5 -1.5], 'k','linewidth',2);

hold on

plot([.5 3.5],[-2.5 -2.5], 'k','linewidth',2)

plot([1.5 1.5],[-.5 -3.5], 'k','linewidth',2)

plot([2.5 2.5],[-.5 -3.5], 'k','linewidth',2)

hold off

axis off

% Obtain first move

move = input('enter player 1 move [r,c] ');

r = move(1);

c = move(2);

board(r,c) = 1;

text(c,-r,'X','horizontalalignment','center','fontsize',20)

% Start loop with 2nd player

for turn = 1:4

move = input('enter player 2 move [r,c] ');

r = move(1);

c = move(2);

board(r,c) = -1;

text(c,-r,'O','horizontalalignment','center','fontsize',20)

% Check for victory by 0, 2nd player

result = [sum(board), sum(board) ];

result(1) = board(1,1) + board(2,2) + board(1,3);

result(2) = board(2,1) + board(2,2) + board(2,3);

result(3) = board(3,1) + board(3,2) + board(3,3);

result(4) = board(1,1) + board(2,1) + board(3,1);

result(5) = board(2,1) + board(2,2) + board(2,3);

result(6) = board(1,3) + board(2,3) + board(3,3);

result(7) = board(1,1) + board(2,2) + board(3,3);

result(8) = board(1,3) + board(2,2) + board(3,1);

if any(result == -3)

disp('player 2 wins')

break

end

% Repeat for player 1

move = input('enter player 1 move [r,c] ');

r = move(1);

c = move(2);

board(r,c) = 1;

text(c,-r,'X','horizontalalignment','center','fontsize',20)

% Check for victory for X, 1st player

result = [sum(board), sum(board) ];

result(1) = board(1,1) + board(2,2) + board(1,3);

result(2) = board(2,1) + board(2,2) + board(2,3);

result(3) = board(3,1) + board(3,2) + board(3,3);

result(4) = board(1,1) + board(2,1) + board(3,1);

result(5) = board(2,1) + board(2,2) + board(2,3);

result(6) = board(1,3) + board(2,3) + board(3,3);

result(7) = board(1,1) + board(2,2) + board(3,3);

result(8) = board(1,3) + board(2,2) + board(3,1);

if any(result == 3)

disp('player 1 wins')

break

end

% Checks for draw

if all(result ~= 3) & (sum(sum(abs(board))) == 9)

disp('nobody wins')

end

请先登录，再进行评论。

请先登录，再回答此问题。

Answer 1

the cyclist 2016-11-25

2
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/313999-help-with-tictactoe-code#answer_244717

在 MATLAB Online 中打开

I did not evaluate your entire code, but I can see that this line

result(1) = board(1,1) + board(2,2) + board(1,3)

should be this instead:

result(1) = board(1,1) + board(2,2) + board(3,3)

2 个评论
显示无隐藏无

Charly Perez 2016-11-25

I'm confused how does that make the board read it correctly if that can't be a winning possibility.

the cyclist 2016-11-25

编辑：the cyclist 2016-11-25

在 MATLAB Online 中打开

Oops, I see that you have that result, which is one of the diagonals, already listed as result(7).

However, your current result(1) is a mistake. It should actually be

result(1) = board(1,1) + board(1,2) + board(1,3)

which is a winning combination missing from your list.

(Sorry for my earlier error.)

请先登录，再进行评论。

HELP with TICTACTOE code

4 个评论
显示 2更早的评论隐藏 2更早的评论

回答（1 个）

2 个评论
显示无隐藏无

另请参阅

类别

标签

Community Treasure Hunt

HELP with TICTACTOE code

4 个评论 显示 2更早的评论隐藏 2更早的评论

回答（1 个）

2 个评论 显示 无隐藏 无

另请参阅

类别

标签

Community Treasure Hunt

4 个评论
显示 2更早的评论隐藏 2更早的评论

2 个评论
显示无隐藏无