Problem plotting sinc function.

9 次查看(过去 30 天)
Hi, I'd like to plot the following function: 400/pi*sinc^2(20sin(x))*cos^2(x) for x between -0.5 and 0.5. To that end, I wrote the following code, which unfortunately doesn't yield a result similar to that in attached image:
x = -0.5:0.1:0.5;
plot(x,(400/pi)*(cos(x*pi)).^2.*(sinc(20*sin(x*pi))).^2);
I get a triangular graph instead with no sinusoidal decay. I'd appreciate some assistance with this simple task.

采纳的回答

Stephen23
Stephen23 2016-11-27
编辑:Stephen23 2016-11-27
There is no problem with your function, however you only calculated eleven data points (check the length of x), which gives a very triangular plot because it cannot represent the detail of the curve that you want. You need to increase how many points you calculate, such as this which generates one hundred and one data points:
x = -0.5:0.01:0.5; % <- changed the step to 0.01
y = (400/pi)*cos(x*pi).^2.*sinc(20*sin(x*pi)).^2;
plot(x,y);

更多回答(0 个)

类别

Help CenterFile Exchange 中查找有关 2-D and 3-D Plots 的更多信息

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by