Uninterrupted segment length?
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Let's say I have an array indexes:
Indexes = [1122221122111211112222222]
How do I get the length of uninterrupted 2s? I want to output to be
output=[ 4 2 1 7]
采纳的回答
bio lim
2016-11-28
For a number that has longer digits, I am not sure. However, if it is within acceptable number of digits
format long
Indexes = [112222112211121];
newIndexes=str2double(regexp(num2str(Indexes),'\d','match'))
coffee = find(diff([-1 newIndexes -1]) ~= 0);
length = diff(coffee);
output = length(1+(newIndexes(1)==1):2:end);
The output is:
output =
4 2 1
更多回答（1 个）
Roger Stafford
2016-11-28
编辑：Roger Stafford
2016-11-28
f = find(diff([false,Indexes==2,false])~=0);
output = f(2:2:length(f))-f(1:2:length(f));
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