Error with if elseif statements
显示 更早的评论
My program is set up to ask the user for an input variable, as follows:
GOAL=input('WHAT IS YOUR GOAL?(FIT=FITNESS, FB=FAT BURN, N=NEITHER): ','s');
Then, I wrote an if, elseif statement written as:
if GOAL==('FIT')
I wrote the same thing for if GOAL==('FB') and if GOAL==('N'), and each is followed by functions to be executed for whichever the user chooses.
The error message that I am getting says:
Error using == Matrix dimensions must agree.
Am I approaching it wrong? Anything helps, thanks.
1 个评论
Vaibhav Sharma
2018-2-18
I get the exact message for a different function of question answering
采纳的回答
bio lim
2016-11-30
I suggest you to use strcmp
GOAL=input('WHAT IS YOUR GOAL?(FIT=FITNESS, FB=FAT BURN, N=NEITHER):\n ','s');
if strcmp(GOAL, 'FITNESS')
sprintf('GOOD')
elseif strcmp(GOAL, 'FB')
sprintf('ALSO GOOD')
else strcmp(GOAL, 'N')
sprintf('WHAT YOU SEEK HUMAN')
end
2 个评论
Bree
2016-11-30
Vaibhav Sharma
2018-2-18
I too am forced to thank you for making me aware of that function
更多回答（1 个）
Daniel kiracofe
2016-11-30
0 个投票
In matlab, strings are arrays of characters. Two strings with different lengths have different array dimensions. e.g.
'dog' is a 3x1 character array.
'bird' is a 4x1 character array
So something like this
if ('dog' == 'bird')
will give an error because you are trying to compare a 3x1 array with a 4x1 array, and to compare arrays they must have the same length.
try the strcmp() function instead. i.e
if strcmp(GOAL, 'fit')
类别
在 帮助中心 和 File Exchange 中查找有关 Operators and Elementary Operations 的更多信息
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!
Translated by 
