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Too many output arguments.Why i am getting this issue

2 次查看（过去 30 天）
Sohaib naeem
Sohaib naeem 2016-12-4
关闭： MATLAB Answer Bot 2021-8-20
function [T,Y] = taylor(f,a,b,ya,m)
syms t y
dfs(1) = symfun(f, [t y]);
for k=1:3
dfs(k+1) = diff(dfs(k),t)+f*diff(dfs(k),y);
end
df = matlabFunction(symfun(dfs,[t y]));
h = (b - a)/m;
T = zeros(1,m+1);
Y = zeros(1,m+1);
T(1) = a;
Y(1) = ya;
for j=1:m
tj = T(j);
yj = Y(j);
D = df(tj,yj);
Y(j+1) = yj + h*(D(1)+h*(D(2)/2+h*(D(3)/6+h*D(4)/24)));
T(j+1) = a + h*j;
end
end
and i m solving f=y-t^2+1
  1 个评论
Image Analyst
Image Analyst 2016-12-4
Why didn't you include the error message? You included only a small, virtually useless part of it. Please include ALL THE RED TEXT, after you read this if course. Also show the code you use to call your taylor() function.

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回答（2 个）

Tamir Suliman
Tamir Suliman 2016-12-5
I m not sure exactly but check this code I think you might some thing you initalize to sum the variables then store it again to add it next time
function [T,Y] = taylor(f,a,b,ya,m)
syms t y
dfs(1) = symfun(f, [t y]);
for k=1:3
dfs(k+1) = diff(dfs(k),t)+f*diff(dfs(k),y)
end
df = matlabFunction(symfun(dfs,[t y]));
h = (b - a)/m;
T = zeros(1,m+1);
Y = zeros(1,m+1);
T(1) = a;
Y(1) = ya;
tj=0;yj=0;
for j=1:m
D = df(tj,yj);
Y(j+1) = yj + h*(D(1)+h*(D(2)/2+h*(D(3)/6+h*D(4)/24)));
T(j+1) = a + h*j;
tj = T(j);
yj = Y(j);
end
Tj=tj
Yj=yj
Image Analyst
Image Analyst 2016-12-5
My guess is you called it expecting 3 output arguments, like this:
[T, Y, thirdArg] = taylor(f,a,b,ya,m);
but your code only returns T and Y, not thirdArg.

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