How can I read the actual analog read?

54 次查看(过去 30 天)
Hi, MathWorks communities.
I have a question regarding the "readVoltage(a, ' ') command. When I run my code it shows a voltage data. But when I try to find the maximum or minimum value it shows something else. Can anyone tell me why it happens like that?
clear all;
a = arduino();
for r = 1:10
H(1,r) = readVoltage(a , 'A0')
pause(1);
end
ts = timeseries(H(1,:),1:length(H)); %(data)(time)
save('ardu1','ts','-v7.3')
This is the answer from command window.
H =
Columns 1 through 6
0.2639 0.2639 0.2639 0.2639 0.2639 0.2639
Columns 7 through 10
0.2639 0.2639 0.2688 0.2639
>> maximum = max('ardu1')
maximum =
117
>> minimum = min('ardu1')
minimum =
49
  1 个评论
SyukriY
SyukriY 2016-12-5
Because I want to calculate the temperature using the LM35 sensor. So, the calculation is like this.
temp = (5.0 * analogRead(A0) * 100.0) / 1024;
because the value from the analog read is like this somehow.
169 296 300 299 302

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采纳的回答

SyukriY
SyukriY 2016-12-15
You can actually read the analog value using readVoltage.
You just need to make some calculation.
analog = readVoltage * (1023 / 5);

更多回答(1 个)

Walter Roberson
Walter Roberson 2016-12-5
max('ardu1') means to apply max() to the vector that is the character string 'a', 'r', 'd', 'u', '1'.
There is no MATLAB operator for finding the max() of a .mat file.
Consider max(H)
  4 个评论
SyukriY
SyukriY 2016-12-5
The data is stored in H. But the value is from 'readVoltage'. In the arduino, I get the analog value such as this [169 296 300 299 302]. But by reading the readVoltage the value is not the same. What should I do to get or (maybe convert the readVoltage value) to become the analog value.
SyukriY
SyukriY 2016-12-5
Because I noticed the value is not the same and with that, I cannot proceed with my thermistor calculation to get temperature value.

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