how can i put specific limitation of the output of function in optimization tool algorithms

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mohammed hussein
mohammed hussein 2016-12-5
评论： mohammed hussein 2017-11-1
Hi all can any one help me , i have equation regarding about optimization. for example
clear all
clc
fun = @(x)1+x(1)/(1+x(2)) - 3*x(1)*x(2) + x(2)*(1+x(1));
lb = [0,0];
ub = [1,2];
A = [];
b = [];
Aeq = [];
beq = [];
x0 = [0.5,1];
x = fmincon(fun,x0,A,b,Aeq,beq,lb,ub)
my question is how can i make the algorithm work to find the optimal value of x only if the result of output function (fun) just in over than 1 . if there any other optimization logarithm work under my question , please let me know
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mohammed hussein
mohammed hussein 2016-12-6
编辑：mohammed hussein 2016-12-6
thank you for your response
clear all
clc
fun = @(x)1+x(1)/(1+x(2)) - 3*x(1)*x(2) + x(2)*(1+x(1)); lb = [0,0]; ub = [1,2]; A = []; b = []; Aeq = []; beq = []; x0 = [0.5,1]; x = fmincon(fun,x0,A,b,Aeq,beq,lb,ub)
In normal optimization algorithm works to find the optimal parameter (X) that find min value of output (fun). i want the optimization algorithm can work in specific range value of output (fun). "just over 1" of output (fun) .
Alan Weiss
Alan Weiss 2016-12-6
I am sorry, but I do not understand your question. Perhaps use different words or give an example of what is and what is not an output that satisfies you.
Alan Weiss
MATLAB mathematical toolbox documentation

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采纳的回答

Matt J
Matt J 2017-10-12
You can use a non-linear constraint to force fun(x)>=1, but your feasible region would probably consist of disjoint pieces. Because you only have two unknowns, it would probably be pretty easy to do a sweep over these parameters to find a solution close enough to the optimum to avoid getting stuck in the wrong piece.

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