Debugger won't step into software at first line with this code.

2 次查看（过去 30 天）

DJ V 2016-12-10

0
链接

此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/316373-debugger-won-t-step-into-software-at-first-line-with-this-code

评论： Walter Roberson 2016-12-10

My code is:

function n = palin_product( dig,lim )
    if isnumeric(dig)== false
        n = 0;
        return;
    end
    if isnumeric(lim)==false
        n = 0;
        return;
    end
    c = floor(dig)
    multiplier1=10^c;
    multiplier1 = multiplier1-1;
    L=num2string(lim);
    len = length(L)
    if ceil(L/2)-floor(L/2)==0
        nucount=L/2;
    else
        numcount =floor(L/2);
    end
    for q =lim:-1:1
        consider= q;
        L = num2string(q)
        if ceil(L/2)-floor(L/2)==0
            nucount= L/2;
        else
            nucount= floor(L/2);
        end
        test =false;
        for count = 0:nucount-1
            if L(0+count) == L(len-count);
                test =true
            else
                test = false
            end
            if count ==true
                n = q;
            end
        end
    end        
    if test ==false
        n =0;
    end
end

THe description of the problem is:

Matlab will not let me start tracing software to look for errors in its behavior. It won't got to the first "if" statement when I call the function. What is wrong?

2 个评论
显示无隐藏无

Walter Roberson 2016-12-10

It would not stop there if the function is not being called, or if it is being called with too many arguments. Re-check the file name, and make sure that you have dig and lim defined when you invoke the function. Are any error messages being produced?