How to pad all numbers in array ?

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RuiQi
RuiQi 2016-12-11
评论： RuiQi 2016-12-11
How can I pad a vector of number with zeros ? I am able to do it with a for loop but I was wondering if there is a neater way to do it ?
For example,
a = [1 2 3 4 5];
b = sprintf('%06d',a);
gives me '000001000002000003000004000005'
I would like it to be [000001 000002 .....];
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Stephen23
Stephen23 2016-12-11
编辑：Stephen23 2016-12-11
Floating point numeric values do not store explicit leading zeros. Even if you typed them, the zeros have no mathematical significance:
>> [000001,000002]==[1,2]
ans =
1 1

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Stephen23
Stephen23 2016-12-11
b = sprintf(' %06d',a{:});
^ add this space
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Stephen23
Stephen23 2016-12-11
编辑：Stephen23 2016-12-11
There is no simple way to create a cell array of strings, but this works:
c = cellfun(@(n)sprintf('%06d',n),a,'UniformOutput',false)
Or you can read about the undocumented function sprintfc:
http://undocumentedmatlab.com/blog/sprintfc-undocumented-helper-function
RuiQi
RuiQi 2016-12-11
wow sprintfc works very nicely. and i will also read through the cellfun

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Image Analyst
Image Analyst 2016-12-11
What does that mean? If they're strings, fine -- you can have leading zeros. But if it's a number leading zeros are ignored, so printing or using 000003 will be just the same use using 3. So are you looking for a cell array? If so, see the FAQ: http://matlab.wikia.com/wiki/FAQ#What_is_a_cell_array.3F
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RuiQi
RuiQi 2016-12-11
training_set = cell(size(train,1),1);
for i=1:size(train,1)
training_set{i,1} = sprintf('%06d',train(i));
end
this works but im looking for a method without using the for loop if its possible
RuiQi
RuiQi 2016-12-11
b = sprintf('%06d',[a{:}]);
doesnt work as well

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