minimum of all iterations

2 次查看(过去 30 天)
A=[1 0 0 1 0 1 1
0 1 1 1 0 0 1
1 0 0 1 1 0 0
1 0 0 0 1 0 1
1 1 0 0 0 1 0
0 1 0 0 0 1 1];
demand=[600;550;620;500;590;600]
for k=1:100
B=randi([0,1],7,3)
C=A*B
C(C>=1)=1
D=sum(C,2)
D1=sum(bsxfun(@times,D,demand))
end
I want to get the minimum value of D1 from all iterations

采纳的回答

David Barry
David Barry 2016-12-15
编辑:David Barry 2016-12-15
A=[1 0 0 1 0 1 1
0 1 1 1 0 0 1
1 0 0 1 1 0 0
1 0 0 0 1 0 1
1 1 0 0 0 1 0
0 1 0 0 0 1 1];
demand=[600;550;620;500;590;600];
numIterations = 100;
D1 = zeros(numIterations, 1);
for k=1:numIterations
B=randi([0,1],7,3);
C=A*B;
C(C>=1)=1;
D=sum(C,2);
D1(k)=sum(bsxfun(@times,D,demand));
end
minVal = min(D1);

更多回答(1 个)

Walter Roberson
Walter Roberson 2016-12-15
D1(k)=sum(bsxfun(@times,D,demand));
and after the loop, min(D1)

类别

Help CenterFile Exchange 中查找有关 Wind Power 的更多信息

标签

产品

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by