concatenation of matrix and final value

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summyia qamar
summyia qamar 2016-12-16
评论： summyia qamar 2016-12-16
%%minimize intercellular movements
part_machine=
[1 0 0 1 0 1 1; 0 1 1 1 0 0 1; 1 0 0 1 1 0 0; 1 0 0 0 1 0 1; 1 1 0 0 0 1 0; 0 1 0 0 0 1 1]
demand=[600;550;620;500;590;600]; numIterations=100;
movement_cost=zeros(numIterations,1)
for k=1:numIterations
rand_cell_assigntomachines=randi([0,1],7,3);
Part_cell=part_machine*rand_cell_assigntomachines;
Part_cell(Part_cell>=1)=1;
no_of_movements=sum(Part_cell,2)-1;
movement_cost=sum(bsxfun(@times,no_of_movements,demand))
end
minval=min(movement_cost)
I want to get the answer of min movement_cost along with the associated rand_cell_assigntomachines matrix from which thi answer is generated..is there any way? because rand_cell_assigntomachines ia a matrix of 7x3 while movement cost is just one value.

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采纳的回答

KSSV
KSSV 2016-12-16
Is this okay?
minval=min(movement_cost)
[rand_cell_assigntomachines minval(ones(7,1))]

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