Extracting number from a string

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Anh Tran
Anh Tran 2016-12-16
编辑： Stephen23 2022-11-3
How can I extract the number 1 from the string 'M1' ?

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Stephen23
Stephen23 2016-12-16
Here are two very simple methods:
>> str = 'M1';
>> sscanf(str,'M%d')
ans = 1
>> str(2)-'0'
ans = 1
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Anh Tran
Anh Tran 2016-12-16
Thanks for the great answer! But can you also explain the code for me?
Stephen23
Stephen23 2016-12-17
sscanf reads the numeric values in a string. Read its documentation to know how it works.
The second method subtracts the character code for the character '0' from the second character of the string. This is a simple way of converting digits into a vector of values.

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更多回答（3 个）

José-Luis
José-Luis 2016-12-16
编辑：José-Luis 2016-12-16
result = 'M1' - '0';
result(result < 0 | result > 9) = [];
  1 个评论
Anh Tran
Anh Tran 2016-12-16
Thanks for the great answer! But can you also explain the code for me?

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Pierre Harouimi
Pierre Harouimi 2022-11-2
You can use pattern from R2020b:
numbers = str2double(extract(string, digitsPattern));
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Image Analyst
Image Analyst 2022-11-2
编辑：Image Analyst 2022-11-2
Ran in:
Example:
string = 'abc123def456789ghi'
string = 'abc123def456789ghi'
numbers = str2double(extract(string, digitsPattern))
numbers = 2×1
123 456789
It would be nice if they made a little wrapper function for that, since it's hard to remember. Something simple like
numbers = extractNumbers(string);
would be easier for most people I think, than having to know about digitsPattern, extract, str2double, and then having to nest them all together.
Stephen23
Stephen23 2022-11-3
编辑：Stephen23 2022-11-3
"Something simple like... would be easier for most people I think..."
The devil is in the details, because it really depends on what you define as a "number". Some users will want to match fractional digits (which probably means selecting for e.g. comma vs dot vs comma|dot), whereas others will want to match only integers and to treat commas/dots as non-numeric. Ditto exponent notation, NaNs, Infs, other bases, fixed-width numbers, various Unicode minus/plus signs, etc.
So it turns out to be not very simple at all, once the different "number" formats are considered. The user specifying a regular expression or MATLAB pattern is one way to give them that control, by making those choices explicit.

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Image Analyst
Image Analyst 2016-12-16
Here are two ways, depending on if you want the extracted "1" to be a character (string) or a number:
str = 'M1' % First define the string.
str1 = str(2) % Gives a character
dbl1 = str2double(str(2)) % Give a number (double)

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