Automatically creating and editing Fields of struct with for Loop
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That is my current code:
%%Struct Problem
for k=1:5
struct.i(k).m=rand;
struct.i(k).n=rand;
struct.i(k).o=rand;
struct.i(k).p=rand;
struct.i(k).q=rand;
end
And I want to automate the steps in a way like this:
for k=1:5
for a=['m','n','o','p','q']
struct.i(k).a=rand;
end
end
How can I automatically create and edit fields with a for loop?
1 个评论
Stephen23
2016-12-17
Dynamic fieldnames are explained in the documentation:
采纳的回答
Image Analyst
2016-12-17
What's wrong with the first way? That's the method I'd prefer. It's much more straightforward and intuitive and easy to understand than using dynamic field names.
I really don't recommend dynamic field names, but if you insist, it is possible, though a lot more complicated than your first method:
% Initialize just one struct with 5 fields.
s = struct('m',0, 'n',0, 'o',0, 'p',0, 'q',0)
letters = {'m', 'n' 'o','p','q'}
size(s)
% Now make an array of 10 of them.
myStruct = repmat(s, 1, 10) % Whatever
size(myStruct)
for k = 1 : size(myStruct, 2)
for lIndex = 1 : length(letters)
fprintf('Assigning field %s to structure #%d\n', letters{lIndex}, k)
myStruct(k).(letters{lIndex}) = rand;
end
end
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